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a^2-7a-256=0
a = 1; b = -7; c = -256;
Δ = b2-4ac
Δ = -72-4·1·(-256)
Δ = 1073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{1073}}{2*1}=\frac{7-\sqrt{1073}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{1073}}{2*1}=\frac{7+\sqrt{1073}}{2} $
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